69. Mercury 3 g is placed between two parallel glass pl

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Uploaded: 24.03.2014
Content: fiz007_69.doc (48,5 kB)

Description

69. Mercury 3 g is placed between two parallel glass plates. Determine the force that must be applied to flatten to a thickness of a drop of d = 0.1 mm. Mercury does not wet glass. Mercury density ρ = 13,6 g / cm3, and its surface tension σ = 0,5 N / m

Additional information

Detailed solution. Decorated in Microsoft Word 2003. (Target decided to use formula editor)

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