DHS 15.1 - Option 17. Decisions Ryabushko AP

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DHS 15.1 - Option 17. Decisions Ryabushko AP

1. Dana function u (M) = u (x, y, z) and the point M1, M2. Calculate: 1) The derivative of this function in the direction of the point M1 M1M2 vector; 2) grad u (M1)

1.17. u (M) = x - 2y + ez, M1 (-4, -5, 0), M2 (2, 3, 4)

2. Calculate the surface integral of the first kind on the surface S, where S - part of the plane (p), cut off by the coordinate planes.

 (P): 3x - 2y + 2z = 6

3. Calculate the surface integral of the second kind.

 where S - the surface of the cone z2 = x2 + y2 (normal vector n which forms an acute angle with the unit vector k), cut off by the plane z = 0 and z = 3.

4. Calculate the flow vector field a (M) through the outer surface of the pyramid formed by plane (p) and the coordinate planes in two ways: a) determination using flow; b) using the formula Ostrogradskii - Gauss.

4.17. and (M) = (x + y) i + (y + z) j + 2 (z + x) k, (p): 3x - 2y + 2z = 6

Additional information

Detailed solution. Decorated in Microsoft Word 2003 (Quest decided to use the formula editor)

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