DHS 15.1 - Option 19. Decisions Ryabushko AP

Affiliates: 0,02 $how to earn
Pay with:
i agree with "Terms for Customers"
Sold: 2 last one 20.12.2017
Refunds: 0

Uploaded: 09.11.2016
Content: 19v-IDZ15.1.doc 216 kB


DHS 15.1 - Option 19. Decisions Ryabushko AP

1. Dana function u (M) = u (x, y, z) and the point M1, M2. Calculate: 1) The derivative of this function in the direction of the point M1 M1M2 vector; 2) grad u (M1)

1.19. u (M) = 3x2yz3, M1 (-2, -3, 1), M2 (5, -2, 0)

2. Calculate the surface integral of the first kind on the surface S, where S - part of the plane (p), cut off by the coordinate planes.

 (P): x - y + z = 2

3. Calculate the surface integral of the second kind.

 where S - the surface of the cone x2 + z2 = y2 (normal vector n which forms an obtuse angle with the unit vector j), clipping plane y = 0, y = 1.

4. Calculate the flow vector field a (M) through the outer surface of the pyramid formed by plane (p) and the coordinate planes in two ways: a) determination using flow; b) using the formula Ostrogradskii - Gauss.

4.19. and (M) = (2x - z) i + (y - x) j + (x + 2z) k, (p): x - y + z = 2

Additional information

Detailed solution. Decorated in Microsoft Word 2003 (Quest decided to use the formula editor)


No feedback yet.
1 month 3 months 12 months
0 0 0
0 0 0
In order to counter copyright infringement and property rights, we ask you to immediately inform us at support@plati.market the fact of such violations and to provide us with reliable information confirming your copyrights or rights of ownership. Email must contain your contact information (name, phone number, etc.)