IDZ 10.2 - Option 28. Decisions Ryabushko AP

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Uploaded: 10.03.2014
Content: 28v-idz10.2.doc (215,5 kB)

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1. Find the equation of the tangent plane and the normal to the given surface S at the point M0 (x0, y0, z0)
1.28 S: z = x2 + y2 - 4xy + 3x - 15, M0 (-1, 3, 4)

2. Find the second partial derivatives of the functions. Ensure that z "xy = z" yx
2.28 z = arcctg (x - 4y)

3. To verify whether the above equation the function u.
4. Examine the following function extremum.
4.28 z = xy - 3x2 - 2y2

5. Find the maximum and minimum values of the function z = z (x, y) in D, given the limited lines.
5.28 z = 5x2 - 3xy + y2 + 4, D: x = -1, x = 1, y = -1, y = 1

Additional information

Detailed solution. Decorated in Microsoft Word 2003 (Target decided to use formula editor)

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