КО193 To a solution of NH4Cl was added 25.00 cm3 NaOH,

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193. To a solution of NH4Cl was added 25.00 cm3 NaOH, T (NaOH) = 0,004500. Then, from the solution by boiling NH3 was removed. On titration of excess NaOH matter remaining 8.50 cm3 HCl (T (HCl) = 0,003850). Calculate the content of NH3 solution NH4Cl.


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