MCH 265

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Uploaded: 23.09.2014
Content: 40923084611870.rar (5,84 kB)

Description

265. Gas, being working substance in Carnot´s cycle, I received warmth of Q1=4,38kdzh from a teplootdatchik and I made work A=2,4kdzh. To determine teplootdatchik temperature, if T2 heat receiver temperature = 273 K.

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The solution of a task 265 is typed on the computer.

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