MCH 441

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Uploaded: 28.09.2014
Content: 40928083607330.rar (30,48 kB)

Description

441. The proton flew in crossed at an angle φ = 120 ° magnetic (B = 50mtl) and electric (E = 20kv/m) fields. To define acceleration and a proton if its speed of V (|V | = 4×105 m/s) is perpendicular to vectors E and B.

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The solution of a task 441 is typed on the computer.

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