Proton, accelerated by the electric field length of 1 =

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Proton, accelerated by the electric field length d1 = 10 cm and intensity E1 = 100 V / m, gets laterally field strength E2 = 20 V / m. Find: 1) the proton shift of the initial direction of motion during t = 5 ms; 2) its kinetic energy at this time.

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Task 31236. Detailed solution with a short recording conditions, laws and formulas used in the decision, the withdrawal of the calculation formula and the answer.
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