The electric power of 20 kW percentage of heat loss

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The electric power of 20 kW percentage of heat loss through the walls is 0.3. The inner surface of the furnace (area S = 1,0 m ^ 2) is lined with refractory, whose absorbance is 0.35. Determine at what wavelength at the nominal operating mode to the maximum of radiation energy, and to find the maximum spectral density of the radiosity calculated on the wavelength interval of 1 nm near lambda (max).

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Task 50269. Detailed solution with a short recording conditions, laws and formulas used in the decision, the withdrawal of the calculation formula and the answer.
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